Solving for an unknown variable
How best can I approach this question?
A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to make a 34.5% water/bromine solution?
Let x= water and y= the salt solution
"If the chemist needs 30 liters of the mixture"
x + y = 30 ...is that right?
Re: Solving for an unknown variable
Easier this way: let w = water ; then bromine = 30 - w
Originally Posted by KayPee
Can you turn that into an equation, then solve for w?
w @ .45
30-w @ .10
30 @ .345