Simultaneous non-linear equations.

**pephiroth** · September 19th 2011, 07:52 AM

{5xy(x² + y²) = -160
{x² + 5xy +y² = -12
???

**Siron** · September 19th 2011, 08:06 AM

What do you have to do? Solve the system? ...

**pephiroth** · September 19th 2011, 08:12 AM

Yes

**Siron** · September 19th 2011, 08:25 AM

The first thing I noticed is that you recognize two equal parts in both equations, the $5xy$ part and $x^2+y^2$

So you can 'simplify' the system by saying, let $x^2+y^2=a$ and $5xy=b$ therefore you get the two simultaneous equations:
$b\cdot a=-160$ (1)
$a+b=-12$ (2)

Solve this system and afterwards do the back-substitution.

**pephiroth** · September 19th 2011, 08:33 AM

Thank you very much

**Siron** · September 19th 2011, 11:23 AM

You're welcome!

I'll give you a part of the solution,
Solving the system by reforming (1) to $b$ and substituting this in (2):
$a-\frac{160}{a}=-12$
$\Leftrightarrow a^2-160=-12a$
$\Leftrightarrow a^2+12a-160=0$
Two solutions: $a=8$ or $a=-20$
But we have to reject $a=-20$ because $a=x^2+y^2$ is always >0.
If $a=8$ then $b=-20$

So now you can do the back-substitution and solve it.

Thread: Simultaneous non-linear equations.

LinkBack

Thread Tools

Display

Simultaneous non-linear equations.

Re: No idea

Re: No idea

Re: No idea

Re: No idea

Re: No idea

Similar Math Help Forum Discussions

simultaneous linear equations

Simultaneous Equations, Non Linear Equations and Equations with 3 unknown pronumerals

Simultaneous linear equations

Simultaneous linear equations

Simultaneous and linear equations

Search Tags