# Math Help - Solve the inequality 20-3y > y+4

1. ## Solve the inequality 20-3y > y+4

I am not sure of my workings but here it is:

$20-3y = y+4$
$20-4 = y+3y$
$16=4y$
$y=4$

Therefore, $y>4$

Also, how do I illustrate the answer on a number line? Not quite sure what they are asking for

2. ## Re: Solve the inequality 20-3y > y+4

Originally Posted by FailInMaths
I am not sure of my workings but here it is:

$20-3y > y+4$
$20-4 > y+3y$
$16>4y$
$y<4$

...

Also, how do I illustrate the answer on a number line? Not quite sure what they are asking for
The above is how it should read. Why did you switch to "=" ?
To graph y < 4
Mark "4" on a number line. Either circle it, or put a " ) " right parenthesis there, and then shade/draw a line to the left (where "lesser" numbrs are)

3. ## Re: Solve the inequality 20-3y > y+4

$20-3y>y+4\Leftrightarrow 16>4y \Leftrightarrow 4>y$ so the solutions are the elements of $(-\infty,4)$ .

Edited: Sorry, I didn't see TheChaz's post.

4. ## Re: Solve the inequality 20-3y > y+4

Originally Posted by TheChaz
The above is how it should read. Why did you switch to "=" ?
To graph y < 4
Mark "4" on a number line. Either circle it, or put a " ) " right parenthesis there, and then shade/draw a line to the left (where "lesser" numbrs are)
Oh, I get it now, thanks!

5. ## Re: Solve the inequality 20-3y > y+4

Originally Posted by FernandoRevilla
$20-3y>y+4\Leftrightarrow 16>4y \Leftrightarrow 4>y$ so the solutions are the elements of $(-\infty,4)$ .

Edited: Sorry, I didn't see TheChaz's post.
No need for apologies, especially since you included the solution in interval notiation!