Solve the inequality 20-3y > y+4

I am not sure of my workings but here it is:

$\displaystyle 20-3y = y+4$

$\displaystyle 20-4 = y+3y$

$\displaystyle 16=4y$

$\displaystyle y=4$

Therefore, $\displaystyle y>4$

Also, how do I illustrate the answer on a number line? Not quite sure what they are asking for

Re: Solve the inequality 20-3y > y+4

Quote:

Originally Posted by

**FailInMaths** I am not sure of my workings but here it is:

$\displaystyle 20-3y > y+4$

$\displaystyle 20-4 > y+3y$

$\displaystyle 16>4y$

$\displaystyle y<4$

...

Also, how do I illustrate the answer on a number line? Not quite sure what they are asking for

The above is how it should read. Why did you switch to "=" ?

To graph y < 4

Mark "4" on a number line. Either circle it, or put a " ) " right parenthesis there, and then shade/draw a line to the left (where "lesser" numbrs are)

Re: Solve the inequality 20-3y > y+4

$\displaystyle 20-3y>y+4\Leftrightarrow 16>4y \Leftrightarrow 4>y$ so the solutions are the elements of $\displaystyle (-\infty,4)$ .

Edited: Sorry, I didn't see **TheChaz**'s post.

Re: Solve the inequality 20-3y > y+4

Quote:

Originally Posted by

**TheChaz** The above is how it should read. Why did you switch to "=" ?

To graph y < 4

Mark "4" on a number line. Either circle it, or put a " ) " right parenthesis there, and then shade/draw a line to the left (where "lesser" numbrs are)

Oh, I get it now, thanks!

Re: Solve the inequality 20-3y > y+4

Quote:

Originally Posted by

**FernandoRevilla** $\displaystyle 20-3y>y+4\Leftrightarrow 16>4y \Leftrightarrow 4>y$ so the solutions are the elements of $\displaystyle (-\infty,4)$ .

Edited: Sorry, I didn't see **TheChaz**'s post.

No need for apologies, especially since you included the solution in *interval notiation*!