(4a/a^2-b^2) + (2/a-b) / (3/a-b)-(b/a^2-b^2) help plzz asap
Since $\displaystyle a^2- b^2= (a- b)(a+ b)$, $\displaystyle a^2- b^2$ is the least common denominator of all the fractions. Start by multiplying both numerator and denominator by $\displaystyle a^2- b^2$.$\displaystyle \frac{\frac{4a}{a^2-b^2} + \frac{2}{a-b}}{\frac{3}{a-b}-\frac{b}{a^2-b^2}}$