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Math Help - simplifying Complex Fraction.

  1. #1
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    simplifying Complex Fraction.

    (4a/a^2-b^2) + (2/a-b) / (3/a-b)-(b/a^2-b^2) help plzz asap
    Last edited by mr fantastic; September 17th 2011 at 05:30 PM. Reason: Deleted begging for help asap etc.
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  2. #2
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    Re: simplifying Complex Fraction.

    Is this your question?

    \frac{4a}{a^2-b^2}+\frac{\frac{2}{a-b}}{\frac{3}{a-b}}-\frac{b}{a^2-b^2}

    As it stands, the problem statement is extremely unclear.
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  3. #3
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    Re: simplifying Complex Fraction.

    ... or this?

    \frac{\frac{4a}{a^2-b^2} + \frac{2}{a-b}}{\frac{3}{a-b}-\frac{b}{a^2-b^2}}
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  4. #4
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    Re: simplifying Complex Fraction.

    its the second one. sorry bout the unclarity, i dont know how to write equations on the internet. lol how fatuous of me. anywayz skeeter guessed it right so anyone care to explain? thanks
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  5. #5
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    Re: simplifying Complex Fraction.

    Well, how far can you get on your own?
    We don't know what you know or been taught.
    Is this a problem from math class?
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  6. #6
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    Re: simplifying Complex Fraction.

    \frac{\frac{4a}{a^2-b^2} + \frac{2}{a-b}}{\frac{3}{a-b}-\frac{b}{a^2-b^2}}
    Since a^2- b^2= (a- b)(a+ b), a^2- b^2 is the least common denominator of all the fractions. Start by multiplying both numerator and denominator by a^2- b^2.
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  7. #7
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    Re: simplifying Complex Fraction.

    May be easier (less confusing) to first let x = a^2 - b^2 and y = a - b.
    Simplify as much as you can with those, then substitute back in;
    easier for me, anyway!
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  8. #8
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    Re: simplifying Complex Fraction.

    what i did was i used this rule that a/b + c/d equals ad+cb/bd. I tried to simplify the two fractions seperately but results weren't guud. this is a question for gr.10 math at school.
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  9. #9
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    Re: simplifying Complex Fraction.

    as recommended by Halls of Ivy ...

    \frac{\frac{4a}{a^2-b^2} + \frac{2}{a-b}}{\frac{3}{a-b}-\frac{b}{a^2-b^2}} \cdot \frac{a^2-b^2}{a^2-b^2} = \frac{4a + 2(a+b)}{3(a+b) - b}

    finish it
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