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Math Help - perimeter word problem

  1. #1
    No one in Particular VonNemo19's Avatar
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    perimeter word problem

    The perimeter of a rectangle is 42 feet. If the width of the rectangle is 6 feet less than the length, find the demensions of the rectangle.

    I'm having trouble setting this up. Help?
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  2. #2
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    Re: perimeter word problem

    Name Stuff!

    W = Width of Rectangle
    L = Length of Rectangle

    Now translate!

    "The perimeter of a rectangle is 42 feet." -- Say that in terms of L and W
    "the width of the rectangle is 6 feet less than the length" -- Say that in terms of L and W

    Seriously... WRITE DOWN clear and concise definitions. They WILL save you.
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  3. #3
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    Re: perimeter word problem

    Quote Originally Posted by VonNemo19 View Post
    The perimeter of a rectangle is 42 feet. If the width of the rectangle is 6 feet less than the length, find the demensions of the rectangle.

    I'm having trouble setting this up. Help?
    You are told \displaystyle w = l - 6, and you should know that \displaystyle P = 2l + 2w with \displaystyle P= 42.

    So that means \displaystyle 2l + 2(l - 6) = 42. Solve for \displaystyle l, then use this to solve for \displaystyle w.
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