perimeter word problem

**VonNemo19** · September 17th 2011, 08:13 AM

The perimeter of a rectangle is 42 feet. If the width of the rectangle is 6 feet less than the length, find the demensions of the rectangle.

I'm having trouble setting this up. Help?

**TKHunny** · September 17th 2011, 08:15 AM

Name Stuff!

W = Width of Rectangle
L = Length of Rectangle

Now translate!

"The perimeter of a rectangle is 42 feet." -- Say that in terms of L and W
"the width of the rectangle is 6 feet less than the length" -- Say that in terms of L and W

Seriously... WRITE DOWN clear and concise definitions. They WILL save you.

**Prove It** · September 17th 2011, 08:16 AM

Originally Posted by VonNemo19

The perimeter of a rectangle is 42 feet. If the width of the rectangle is 6 feet less than the length, find the demensions of the rectangle.

I'm having trouble setting this up. Help?

You are told $\displaystyle w = l - 6$ , and you should know that $\displaystyle P = 2l + 2w$ with $\displaystyle P= 42$ .

So that means $\displaystyle 2l + 2(l - 6) = 42$ . Solve for $\displaystyle l$ , then use this to solve for $\displaystyle w$ .

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