The perimeter of a rectangle is 42 feet. If the width of the rectangle is 6 feet less than the length, find the demensions of the rectangle.

I'm having trouble setting this up. Help?

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- Sep 17th 2011, 08:13 AMVonNemo19perimeter word problem
The perimeter of a rectangle is 42 feet. If the width of the rectangle is 6 feet less than the length, find the demensions of the rectangle.

I'm having trouble setting this up. Help? - Sep 17th 2011, 08:15 AMTKHunnyRe: perimeter word problem
Name Stuff!

W = Width of Rectangle

L = Length of Rectangle

Now translate!

"The perimeter of a rectangle is 42 feet." -- Say that in terms of L and W

"the width of the rectangle is 6 feet less than the length" -- Say that in terms of L and W

Seriously... WRITE DOWN clear and concise definitions. They WILL save you. - Sep 17th 2011, 08:16 AMProve ItRe: perimeter word problem
You are told $\displaystyle \displaystyle w = l - 6$, and you should know that $\displaystyle \displaystyle P = 2l + 2w$ with $\displaystyle \displaystyle P= 42$.

So that means $\displaystyle \displaystyle 2l + 2(l - 6) = 42$. Solve for $\displaystyle \displaystyle l$, then use this to solve for $\displaystyle \displaystyle w$.