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Math Help - Solving Equations.

  1. #1
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    Solving Equations.

    I have two questions which I have attempted to do with no success, can you thoroughly explain what to do?

    The length of a swimming pool is 2.5m greater than its width. The pool's perimeter is 29m. Find the lenghth of the pool.

    So, for this one. I knew that the perimeter is 2l + 2w

    so I ended up with this 29 =2(2.5l(w))

    then I don't know what to do after that.

    The second question is

    \frac{x}{5}+1\frac{1}{2}x-\frac{11}{20}=\frac{5x-1}{4}

    Do I turn the mixed fraction into a improper one first then move 5x to the left hand side? then move 11/20 to right hand side so it would be:

    \frac{x}{5}+\frac{3}{2}x+5x=-\frac{11}{20}+\frac{-1}{4}

    Am I right?
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  2. #2
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    Re: Solving Equations.

    Quote Originally Posted by JibblyJabbly View Post
    I have two questions which I have attempted to do with no success, can you thoroughly explain what to do?

    The length of a swimming pool is 2.5m greater than its width. The pool's perimeter is 29m. Find the lenghth of the pool.

    So, for this one. I knew that the perimeter is 2l + 2w

    so I ended up with this 29 =2(2.5l(w))

    then I don't know what to do after that.

    correction ...

    P = 2(L + W)

    P = 2[(2.5+W) + W]

    P = 2(2.5 + 2W)

    P = 5 + 4W


    The second question is

    \frac{x}{5}+1\frac{1}{2}x-\frac{11}{20}=\frac{5x-1}{4}

    Do I turn the mixed fraction into a improper one first then move 5x to the left hand side? then move 11/20 to right hand side so it would be:

    \frac{x}{5}+\frac{3}{2}x+5x=-\frac{11}{20}+\frac{-1}{4}
    \frac{x}{5}+1\frac{1}{2}x-\frac{11}{20}=\frac{5x-1}{4}

    multiply every term by the common denominator to clear the fractions ...

    4x + 30x - 11 =  5(5x-1)

    easier now?
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  3. #3
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    Re: Solving Equations.

    Thank you very much, Skeeter! I almost understand it but:

    P = 2(L + W)

    P = 2[(2.5+W) + W]

    P = 2(2.5 + 2W)

    P = 5 + 4W


    Where did you get the + W from?
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  4. #4
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    Re: Solving Equations.

    It's not so much "+W" as it is "+ 2.5". The problem says "The length of a swimming pool is 2.5m greater than its width." If write W for the width then the length is 2.5 meters greater: W+ 2.5, assuming that width and length are measured in meters.
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  5. #5
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    Re: Solving Equations.

    Quote Originally Posted by jibblyjabbly View Post
    where did you get the + w from?
    p = 2(l + w)

    p = 2[(2.5 + w) + w]
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