:(Hey I'm New to this so here whe go i'm in Pre Ib and i'm in Algerbra 2 honors and i need help with graphing equations using y=mx+b:(

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- Sep 11th 2007, 02:59 PMmeacheeHelp me please
:(Hey I'm New to this so here whe go i'm in Pre Ib and i'm in Algerbra 2 honors and i need help with graphing equations using y=mx+b:(

- Sep 11th 2007, 03:06 PMKrizalid
That's the line in principal form, where is the slope, and where the line intersects to the "y" axis.

Give problems, would be easier to help ya.

P.S.: reduce the size! - Sep 11th 2007, 03:08 PMJhevon
what's with the huge font?

to graph a line, you only need two points (many professors will make you plot several points, but this is not necessary). the easiest (and usually more efficient) points to plot are the intercepts.

in the formula y = mx + b, m is the slope and b is the y-intercept. the y-intercept lies on the y-axis. so you can put a point on the y-axis at the value b.

next we plot the x-intercept. for the x-intercept, we solve for x when y = 0

so we have 0 = mx + b, so x = -b/m. so we can plot that point on the x-axis.

finally, draw a line between the two points and you're done - Sep 12th 2007, 04:40 PMTyRayCooper
Hey Im In School And The Problem Is Simplify

-6(3-d) - Sep 12th 2007, 04:43 PMJhevon
you should post your question in your own new thread.

they want us to simplify here, to do that we must expand. we do this by taking the term on the out side of the brackets and multiplying each of the terms inside the brackets.

-6(3 - d) = (-6)(3) - (6)(-d) = -18 + 6d = 6d - 18