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Math Help - Need some help with simple problem.

  1. #1
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    Need some help with simple problem.

    "Tyler writes this equation to solve a problem:

    3(b - 4) = 9 + 6b,

    He divides both sides of the equation by 3 to get

    b - 4 = 3 +2b

    so he concludes that

    b= -7."

    Okay, well with my math, I did the divide by 3 on both sides, and got

    b-4 = 9+ 6b
    -------
    3

    Not sure if I'm right or not.. anyone.. help please!
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  2. #2
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    Re: Need some help with simple problem.

    3(b - 4) = 9 + 6b

    Dividing both sides by 3 gives


    \frac{3(b - 4)}{3} = \frac{9 + 6b}{3}

    Which simplifies to

    b - 4 = \frac{9 + 6b}{3}

    and then,

    b - 4 = \frac{9 }{3}+ \frac{ 6b}{3}

    b - 4 = 3+ 2b

    continue...
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  3. #3
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    Re: Need some help with simple problem.

    Quote Originally Posted by pickslides View Post
    3(b - 4) = 9 + 6b

    Dividing both sides by 3 gives


    \frac{3(b - 4)}{3} = \frac{9 + 6b}{3}

    Which simplifies to

    b - 4 = \frac{9 + 6b}{3}

    and then,

    b - 4 = \frac{9 }{3}+ \frac{ 6b}{3}

    b - 4 = 3+ 2b

    continue...
    Oh okay. So the original way "Tyler" did it is correct.

    Edit: Actually, he's not correct. The answer is -8, am I correct?
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  4. #4
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    Re: Need some help with simple problem.

    b - 4 = 3+ 2b

    Take 3 from both sides.

    b - 7 =  2b

    Take b from both sides

    - 7 =  b
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