Look at the functions y = |x-5| and y= 10 how many times do they intersect?
Remember that an absolute value leaves positive numbers unchanged and multiplies negative numbers by (-1). Examples,
|5|=5, but |-5|=(-1)*-5=5.
In your question, you have an unknown expression in the absolute value; |x-5|=10, where x is a variable. Since the absolute value is equal to 10, knowing that it leaves positive numbers unchanged and makes negative numbers positive, you know that the inside of the absolute value, namely (x-5) is either 10 or -10, because |10|=10=|-10|.
You therefore have two different solutions for x, x=15 and x=-5, because the inside of the absolute value with these values will give you respectively 10 and -10.
Please learn to use LaTeX tags.
[TEX]|x-5|=10[/TEX] gives
To understand the question you asked one must understand what really means.
If stands for the distance that the number is from .
Thus because is six units from zero.
because is also six units from zero.
So means that
If you have then you must realize that is just some number.
So means that