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Math Help - Help needed with some equations and bedmas

  1. #1
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    Help needed with some equations and bedmas

    Hey jsut need a quick reminder on some Equations like for this question.
    x-3----x
    ___ +__ = 6
    2-------3

    Now i know you have to find the common denominator in this equation, which I believe is 6. so it should be.

    3x-9 + 2x = ?

    Does the 6 need to be change? if so how? I cant remember.

    Plus if you can also help me with this bedmas problem as well.

    -(-2)+2/[-2(-1)]

    I know I have to do the brackets first so -2x-1 is 1
    I believe you do that one first, im just not sure what the - at the left most area of the problem is used for?

    If you wandering im doing college math at the moment and its been quiet a while sinced I did math. If you can help me with this I be so happy right now.
    Last edited by mr fantastic; September 14th 2011 at 05:04 AM. Reason: Title.
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  2. #2
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    Re: Hey need help with some equations and bedmas

    Okay, I think I figured the equation problem. You multiply the 6 with the lowest common denominator which is 6x6. Than you move the -9 to the right side of the =. Thus making it look like this

    3x+2x=36+9

    than you combine.

    5x=45

    divide

    5x--45
    __=__
    5----5

    thus x=9

    I hope I'm right about this one.
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  3. #3
    MHF Contributor Siron's Avatar
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    Re: Hey need help with some equations and bedmas

    Yes, x=9 is correct.
    \frac{x-3}{2}+\frac{x}{3}=6
    \Leftrightarrow \frac{3(x-3)+2x}{6}=6
    \Leftrightarrow 3(x-3)+2x=36
    \Leftrightarrow 3x-9+2x=36
    \Leftrightarrow 5x=45
    \Leftrightarrow x=9
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  4. #4
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    Re: Hey need help with some equations and bedmas

    Thank you, can you help me with the bedmas problem?
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  5. #5
    MHF Contributor Siron's Avatar
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    Re: Hey need help with some equations and bedmas

    You have:
    \frac{-(-2)+2}{-2(-1)}
    Indeed first the brackets (notice --=+), therefore:
    \frac{2+2}{2}
    Therefore we get:
    \frac{4}{2}=2
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  6. #6
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    Re: Hey need help with some equations and bedmas

    Quote Originally Posted by Siron View Post
    You have:
    \frac{-(-2)+2}{-2(-1)}
    Indeed first the brackets (notice --=+), therefore:
    \frac{2+2}{2}
    Therefore we get:
    \frac{4}{2}=2
    Okay I see now thank you so much!
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