Help needed with some equations and bedmas

Hey jsut need a quick reminder on some Equations like for this question.

x-3----x

___ +__ = 6

2-------3

Now i know you have to find the common denominator in this equation, which I believe is 6. so it should be.

3x-9 + 2x = ?

Does the 6 need to be change? if so how? I cant remember.

Plus if you can also help me with this bedmas problem as well.

-(-2)+2/[-2(-1)]

I know I have to do the brackets first so -2x-1 is 1

I believe you do that one first, im just not sure what the - at the left most area of the problem is used for?

If you wandering im doing college math at the moment and its been quiet a while sinced I did math. If you can help me with this I be so happy right now.

Re: Hey need help with some equations and bedmas

Okay, I think I figured the equation problem. You multiply the 6 with the lowest common denominator which is 6x6. Than you move the -9 to the right side of the =. Thus making it look like this

3x+2x=36+9

than you combine.

5x=45

divide

5x--45

__=__

5----5

thus x=9

I hope I'm right about this one.

Re: Hey need help with some equations and bedmas

Yes, $\displaystyle x=9$ is correct.

$\displaystyle \frac{x-3}{2}+\frac{x}{3}=6$

$\displaystyle \Leftrightarrow \frac{3(x-3)+2x}{6}=6$

$\displaystyle \Leftrightarrow 3(x-3)+2x=36$

$\displaystyle \Leftrightarrow 3x-9+2x=36$

$\displaystyle \Leftrightarrow 5x=45$

$\displaystyle \Leftrightarrow x=9$

Re: Hey need help with some equations and bedmas

Thank you, can you help me with the bedmas problem?

Re: Hey need help with some equations and bedmas

You have:

$\displaystyle \frac{-(-2)+2}{-2(-1)}$

Indeed first the brackets (notice --=+), therefore:

$\displaystyle \frac{2+2}{2}$

Therefore we get:

$\displaystyle \frac{4}{2}=2$

Re: Hey need help with some equations and bedmas

Quote:

Originally Posted by

**Siron** You have:

$\displaystyle \frac{-(-2)+2}{-2(-1)}$

Indeed first the brackets (notice --=+), therefore:

$\displaystyle \frac{2+2}{2}$

Therefore we get:

$\displaystyle \frac{4}{2}=2$

Okay I see now thank you so much!