Express f(x) in the form (x-a)g(x)

So I have to do what it says in the title in order to continue to answer the rest of this question.

f(x) = x^2 - 4x - 3

And I need to express that in the form of a product of

(x-3)g(x)

I have no idea how to find g(x) so any hints would be much appreciated.

As an aside, I am aware it would be much easier if the question was x^2-4x+3, but I have double and triple checked my math to get up to this point and that is definitely not the question.

Do long (or synthetic) division of f(x) by (x - 3)

Thanks,

so g(x) = x - 1 - 6/x-3

?

Quote:

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Originally Posted by Perfection

Thanks,

so g(x) = x - 1 - 6/x-3

?

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Indeed.

thank you