$\displaystyle 10^{x}+10^{x-1}=0.11$
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Rewrite: $\displaystyle 10^{x}+10^{x-1}=0,11$ $\displaystyle \Leftrightarrow 10^{x}+10^{x}\cdot 10^{-1}=0,11$ $\displaystyle \Leftrightarrow 10^{x}(1+10^{-1})=0,11$ Continue.
Have you solved it? ...
yeap/ its x=-1 thank you
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