the problem is (c+3/c)^2 I'm trying to use the rules so i squared the first term c^2 then this is where i get stuck, double the product of the two terms, its 6 right? then square the last term which would be 9/c^2 do the c^2 cancel out to make the answer 6+9? i tried 15 as my answer on the online system and it was wrong. i only have a few more tries left and I'm not sure what else i could do to solve the problem?
Hello there,
I assume that the expression is:
.
As you said correctly, square the first term:
.
Next, double the product of the two terms:
Finally, square the last term to get:
.
Notice that when you add only the first and third term above together, you get:
(I ignore the second term just so you can see the expression below)
.
Do you see anything that can be simplified? In other words, does anything actually cancel?
I hope that this helps.