1. ## Simplyfying the expression?

How would I simplify this expression.

4 root((g^3 h^4))/((4r^14))

This is all under the 4 root

I did this

4 root(g^3 h^3 h^4)

h 4 root(g^3 h^3)

4 root((4r^14))

4 root(2 r^2 r^12)

r^3 4 root (2r^2)

But I am stuck?

2. ## Re: Simplyfying the expression?

Originally Posted by homeylova223
How would I simplify this expression.

4 root((g^3 h^4))/((4r^14))

This is all under the 4 root

I did this

4 root(g^3 h^3 h^4)

h 4 root(g^3 h^3)

4 root((4r^14))

4 root(2 r^2 r^12)

r^3 4 root (2r^2)

But I am stuck?
$\displaystyle \sqrt[4]{\frac{g^3 h^4}{4r^{14}}} = \frac{h}{r^3} \sqrt[4]{\frac{g^3}{4r^2}}$

3. ## Re: Simplyfying the expression?

Originally Posted by homeylova223
How would I simplify this expression.

4 root((g^3 h^4))/((4r^14))

This is all under the 4 root

I did this

4 root(g^3 h^3 h^4)
How did "h^4" become "h^3 h^4"?

h 4 root(g^3 h^3)
Apparently "4 root" means "fourth root". Normally, "4 root" would be interpreted as "4 times the square root". But I still have no idea where that remaining "h^3" came from

[quote]4 root((4r^14))

4 root(2 r^2 r^12)

r^3 4 root (2r^2)
Okay, that is right for the denominator

But I am stuck?
It was a fraction, right? So write what you have as a fraction. I don't think anything will cancel.

4. ## Re: Simplyfying the expression?

Sorry what I meant way was to take out h^4 and make it h. Outside the radical.