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Math Help - Simplyfying the expression?

  1. #1
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    Simplyfying the expression?

    How would I simplify this expression.

    4 root((g^3 h^4))/((4r^14))

    This is all under the 4 root

    I did this

    4 root(g^3 h^3 h^4)

    h 4 root(g^3 h^3)

    4 root((4r^14))

    4 root(2 r^2 r^12)

    r^3 4 root (2r^2)

    But I am stuck?
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  2. #2
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    Re: Simplyfying the expression?

    Quote Originally Posted by homeylova223 View Post
    How would I simplify this expression.

    4 root((g^3 h^4))/((4r^14))

    This is all under the 4 root

    I did this

    4 root(g^3 h^3 h^4)

    h 4 root(g^3 h^3)

    4 root((4r^14))

    4 root(2 r^2 r^12)

    r^3 4 root (2r^2)

    But I am stuck?
    \sqrt[4]{\frac{g^3 h^4}{4r^{14}}} = \frac{h}{r^3} \sqrt[4]{\frac{g^3}{4r^2}}
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  3. #3
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    Re: Simplyfying the expression?

    Quote Originally Posted by homeylova223 View Post
    How would I simplify this expression.

    4 root((g^3 h^4))/((4r^14))

    This is all under the 4 root

    I did this

    4 root(g^3 h^3 h^4)
    How did "h^4" become "h^3 h^4"?

    h 4 root(g^3 h^3)
    Apparently "4 root" means "fourth root". Normally, "4 root" would be interpreted as "4 times the square root". But I still have no idea where that remaining "h^3" came from

    [quote]4 root((4r^14))

    4 root(2 r^2 r^12)

    r^3 4 root (2r^2)
    Okay, that is right for the denominator

    But I am stuck?
    It was a fraction, right? So write what you have as a fraction. I don't think anything will cancel.
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  4. #4
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    Re: Simplyfying the expression?

    Sorry what I meant way was to take out h^4 and make it h. Outside the radical.
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