(a-3)x+2ay=8a-6

(a+3)x-4ay=6-10a

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- Sep 8th 2011, 12:46 AMdeathmatesystem of equations
(a-3)x+2ay=8a-6

(a+3)x-4ay=6-10a - Sep 8th 2011, 01:16 AMProve ItRe: system of equations
Multiply the first equation by 2 to get

$\displaystyle \displaystyle \begin{align*}2(a - 3)x + 4a\,y &= 16a - 12 \\ (a + 3)x - 4a\,y &= 6 - 10a \end{align*}$

and then you can subtract the second equation from the first to eliminate the $\displaystyle \displaystyle y$ variables.