|3-2x|>|4-x|
->and please someone explain if we can solve inequalities the same way ,for < ,and for > sign?? thanks!
Do you understand that $\displaystyle |2x-3|>|x-4|$ is the same problem?
Recall that $\displaystyle |a-b|=|b-a|$ because that is just the distance between a & b.
This is true: $\displaystyle |a|\ge |b|\text{ if and only if }a^2\ge b^2.$
So solve $\displaystyle (2x-3)^2>(x-4)^2$. Be sure to check the answers on the original.