|x-1|+|x-2|+|x-3|=2
if and if
Similarly,
if and if ,
if and if .
So, if the LHS will be
If the LHS will be
Similarly for the other two ranges.
For the first of these, if This lies outside the range so no solution for that one. Repeat for the other three.
now i figured out this , but if i continue like this ,equation has no choice ,none matches ,but in the book choice is =2 , i want to say -> did u forgot to put 1<=x<2 instead 1<x<2 or something like this?? #appreciate your help!