I appreciate the honesty
$\displaystyle a = 5b - 2c(3+b) + c$
$\displaystyle a = 5b - 6c-2bc + c$
Hi Pickslides
I have just realised what the spolier was you installed, however I have been looking at this today and came up with this;
a = 5b - 2c(3+b) + c First I loose the bracket
a = 5b - 6c - 2bc + c Not sure why but in a previous explanation Siron removed a C, so I have followed the same line of reasoning here.
a = 5b - 5c - 2b + c Now the whole point of this is to get "b" on it's own, and I still have 5b and another - 2b, so;
a = 5b - 2b - 5c + c
a = 3b - 5c + c Now I will subtract "C" from both sides
a - c = 3b - 5c From this point forwards I can't get "b" on it's own, so I need to go back to line "3" from the top and start again;
a = 5b - 5c - 2b + c Now this time I will try and subtract 1b
a = 4b - 5c - b + c Now I can subtract "c" from the RHS
a - c = 4b - 5c - b Now I can subtract "b" from the RHS
a - c + b = 4b - 5c Now I can divide both sides by "a - c"
b = 4b - 5c / a - c
How have I done working that lot out, since I knew nothing really last night?
Thanks again for all your help to all who helped and advised
Thanks
David
$\displaystyle a = 5b - 6c+c-2bc $
$\displaystyle a = 5b - 5c-2bc $
$\displaystyle a = 5b -2bc - 5c$
$\displaystyle a = 5\times b -2c\times b - 5c$
$\displaystyle a = b(5 -2c) - 5c$