Thread: Equation problem

Hi!

Could someone please solve this for me and explain how to do?
(3/5)x^2 - 2x -5 = 0

I know how to solve this kind of equations but I don't know how to do when I have (3/5)X^2. Because I'm told to multiply the x-term so that it'll be 1. But if I do that I get 10x. And that'll cause problems later on when I'm supposed to get the square root of ten

Originally Posted by jimutt

Hi!

Could someone please solve this for me and explain how to do?
(3/5)x^2 - 2x -5 = 0

I know how to solve this kind of equations but I don't know how to do when I have (3/5)X^2. Because I'm told to multiply the x-term so that it'll be 1. But if I do that I get 10x. And that'll cause problems later on when I'm supposed to get the square root of ten

multiply every term by 5 to clear the fraction ...

$\displaystyle 3x^2 - 10x - 25 = 0$

factor or use the quadratic formula