(-6+6v+2y)(-2) I was wondering if I'm correct. I'd appreciate your response. $\displaystyle 12-12v-4y+12$
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Originally Posted by HellBunny (-6+6v+2y)(-2) I was wondering if I'm correct. I'd appreciate your response. $\displaystyle 12-12v-4y+12$ Where did that final "+12" come from?
Oh, nice catch there. It was a typo. Thanks! So, is it right? Without the 12 at the end.
Yes it is.
(-6+6v+2y)(-2) = 12 - 12v - 4y
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