Solving equations with indeces (version 2)

Hello everyone,

I have come undone on solving another equation with indices in:

I've a feeling it involves simplifying the numerator and denominator of the second half so that I can multiply with the first half, but I'm doing something wrong.

Help much appreciated.

Re: Solving equations with indeces (version 2)

Quote:

Originally Posted by

**mabentley**

Re: Solving equations with indeces (version 2)

These are all powers of three:

Hence the question is:

Use the laws of indices to simplify