The slope of the line which you're searching is indeed that means we have untill now the equation:
We have to find q this can be done by substituting the given point into the equation:
Therefore the equation of the straight line becomes:
Okay, so I am given that the the equation passes through the point (-4, 2) and is perpendicular to 10x - 2y - 6 = 0. Dolefully I have done the calculations, over and over, producing the same results. I put the equation into slope-intercept and procure y = 5x -3
So, m_1 = 5 and m_2 = -1/5. I then take the new slope and use the point-slope equation and, after all of the calculations, find myself with the resultant: 5x + y + 18 = 0
(they ask it to be formatted into general form). The true answer, according the answer key, is x + 5y - 6 = 0--this can not be true!
The slope of the line which you're searching is indeed that means we have untill now the equation:
We have to find q this can be done by substituting the given point into the equation:
Therefore the equation of the straight line becomes:
It will...go study:
Straight-Line Equations: Point-Slope Form