Find the equation of a line that is perpendicular to another.

Okay, so I am given that the the equation passes through the point (-4, 2) and is perpendicular to 10x - 2y - 6 = 0. Dolefully I have done the calculations, over and over, producing the same results. I put the equation into slope-intercept and procure y = 5x -3

So, m_1 = 5 and m_2 = -1/5. I then take the new slope and use the point-slope equation and, after all of the calculations, find myself with the resultant: 5x + y + 18 = 0

(they ask it to be formatted into general form). The true answer, according the answer key, is x + 5y - 6 = 0--this can not be true!

Re: Find the equation of a line that is perpendicular to another.

The slope of the line which you're searching is indeed that means we have untill now the equation:

We have to find q this can be done by substituting the given point into the equation:

Therefore the equation of the straight line becomes:

Re: Find the equation of a line that is perpendicular to another.

Why wouldn't the point-slope formula work?

Re: Find the equation of a line that is perpendicular to another.

y = -x/5 + b ; substitute -4,2:

b = 6/5

y = -x/5 + 6/5

Take over...

Re: Find the equation of a line that is perpendicular to another.

Re: Find the equation of a line that is perpendicular to another.

Well, what formula is this then:

m= (x - x_1)/(y - Y_1)?

Re: Find the equation of a line that is perpendicular to another.

Quote:

Originally Posted by

**Bashyboy** Why wouldn't the point-slope formula work?

It will...go study:

Straight-Line Equations: Point-Slope Form