Driver A starts his car and accelerates with a constant accelerasion of 0.8 m/s^2.
Driver B starts and follows on a motorcycle from the same spot, 6,0 sec later.
Driver B has got a constant acceleration of 1.8 m/s^2. (Neither of them accelerate higher than 80 km/h)
a) How long does it take driver B to catch up with driver A?
b) How long have they driven when they meet?
c) How fast do each driver drive when they meet?
I have tried the four formulas:
v = at+v0
s = 1/2 (v+v0) * t
s = 1/2 a * t^2 + v0 * t
2 * a * s = v^2 - v0^2
With no luck at all. I am confident that some calculations might be wrong.
All help is appreciated, hopefully a quick response.