Originally Posted by

**skeeter** for driver A ...

$\displaystyle v_A = 0.8t$

$\displaystyle s_A = 0.4t^2$

for driver B ...

$\displaystyle v_B = 1.8(t-6)$

$\displaystyle s_B = 0.9(t-6)^2$

for (a) and (b) , set $\displaystyle s_A = s_B$ , solve for t to find the time driver A's run ... don't forget that driver B's run is $\displaystyle (t-6)$. once you get the time, find the value of $\displaystyle s_A$ and $\displaystyle s_B$ (which should be the same, right?)

for (c) , determine the values of $\displaystyle v_A$ and $\displaystyle v_B$ at the time found above.