I have tried everything I know, but I can't solve this. Can you please show me the right direction?

$\displaystyle \frac{16^\frac{1}{3}*4^\frac{1}{3}}{8}$

Thank you!

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- Sep 9th 2007, 10:18 AMCoachA problem with fractional indices
I have tried everything I know, but I can't solve this. Can you please show me the right direction?

$\displaystyle \frac{16^\frac{1}{3}*4^\frac{1}{3}}{8}$

Thank you! - Sep 9th 2007, 10:27 AMJhevon
- Sep 9th 2007, 10:46 AMCoach
Thank you so much!

But I would still have another question

$\displaystyle \frac{x^{2n+1}*x^\frac{1}{2}}{\sqrt{x^{3n}}}$

Thank you! - Sep 9th 2007, 11:03 AMJhevon
change the square root in the denominator to a power (you know how to do that, right? see my post here)

so we get $\displaystyle \frac{x^{2n+1}*x^\frac{1}{2}}{\sqrt{x^{3n}}} = \frac{x^{2n+1}*x^\frac{1}{2}}{x^\frac {3n}{2}}$

Now continue - Sep 9th 2007, 11:24 AMCoach
ok, so is it like

$\displaystyle x^{2n+1+\frac{1}{2}}-^{\frac{3n}{2}}$ ? - Sep 9th 2007, 12:07 PMJhevon