# Math Help - [(x+1)^2]^3

2. ## Re: [(x+1)^2]^3

EDIT:
What happened? Your previous post dissapeared (also the title)?

What do you have to do now?

3. ## Re: [(x+1)^2]^3

Originally Posted by zfa9675
Laws of exponents say that $[(x+1)^2]^3 = (x+1)^6]$. If you want to expand it use the binomial theorem

$\sum_{k=0}^n (1+x)^n = \binom{n}{k}x^k$

4. ## Re: [(x+1)^2]^3

Originally Posted by e^(i*pi)
laws of exponents say that $[(x+1)^2]^3 = (x+1)^6]$. If you want to expand it use the binomial theorem

$\sum_{k=0}^n (1+x)^n = \sum_{k=0}^n\binom{n}{k}x^k$
edit

5. ## Re: [(x+1)^2]^3

This whole thread is causing confusion due to OP edits, lack of a problem statement etc. People are wasting their time as a result. Thread cloed.

@OP: Post your question properly. Include all of the question, including the problem statement.