A question about how this algebraic rearrangement has been done

**Riazy** · August 31st 2011, 12:09 AM

The expression: 5-3/7*(12-5z) = -1/7 -13/7*z.

Could someone show me how its done.

**Siron** · August 31st 2011, 12:17 AM

I guess the expression is:
$5-\frac{3}{7}\cdot (12-5z)$
Expand $\frac{3}{7}\cdot (12-5z)$ and simplify.

**CaptainBlack** · August 31st 2011, 01:12 AM

Originally Posted by Riazy

The expression: 5-3/7*(12-5z) = -1/7 -13/7*z.

Could someone show me how its done.

Could you please put brackets in so that the expressions on both sides are unambiguous

CB

**CaptainBlack** · August 31st 2011, 01:15 AM

Originally Posted by Siron

I guess the expression is:
$5-\frac{3}{7}\cdot (12-5z)$
Expand $\frac{3}{7}\cdot (12-5z)$ and simplify.

If that is the correct interpretation of the left hand side, then it is not equal to the right hand side (the 13 should be a 15).

CB

Thread: A question about how this algebraic rearrangement has been done