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Math Help - A question about how this algebraic rearrangement has been done

  1. #1
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    A question about how this algebraic rearrangement has been done

    The expression: 5-3/7*(12-5z) = -1/7 -13/7*z.

    Could someone show me how its done.
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  2. #2
    MHF Contributor Siron's Avatar
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    Re: A question about how this algebraic rearrangement has been done

    I guess the expression is:
    5-\frac{3}{7}\cdot (12-5z)
    Expand \frac{3}{7}\cdot (12-5z) and simplify.
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  3. #3
    Grand Panjandrum
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    Re: A question about how this algebraic rearrangement has been done

    Quote Originally Posted by Riazy View Post
    The expression: 5-3/7*(12-5z) = -1/7 -13/7*z.

    Could someone show me how its done.
    Could you please put brackets in so that the expressions on both sides are unambiguous

    CB
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  4. #4
    Grand Panjandrum
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    Re: A question about how this algebraic rearrangement has been done

    Quote Originally Posted by Siron View Post
    I guess the expression is:
    5-\frac{3}{7}\cdot (12-5z)
    Expand \frac{3}{7}\cdot (12-5z) and simplify.
    If that is the correct interpretation of the left hand side, then it is not equal to the right hand side (the 13 should be a 15).

    CB
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