1. ## Deriving the equation

Derive the equation (general form) of all points that are equidistant from the point F(-6,3) and the line y = -5.

Thanks

2. Originally Posted by Mr_Green
Derive the equation (general form) of all points that are equidistant from the point F(-6,3) and the line y = -5.

Thanks
Let $\displaystyle (x,y)$ be such a point. Then what is that distance from this point to $\displaystyle (6,3)$? What is the distance from this point to $\displaystyle y=-5$? Now equate these two quantities and you have your equation.

3. sqrt[(x+6)^2 + (y-3)^2] = sqrt[(0^2) + (y+5)^2]

square both sides

x^2 + 12x + 36 + y^2 - 6y + 9 = y^2 + 10y +25

x^2 + 12x -16y -11 = 0

Is this correct?

4. Originally Posted by Mr_Green
sqrt[(x+6)^2 + (y-3)^2] = sqrt[(0^2) + (y+5)^2]

square both sides

x^2 + 12x + 36 + y^2 - 6y + 9 = y^2 + 10y +25

x^2 + 12x -16y -11 = 0

Is this correct?
the distance of (-6,3) to the line y = -5 is the distance between the points (-6,3) and (-6,-5), you don't really need the formula for this, but you can use it if you want to (we are looking for the shortest distance here, which is a vertical line, so the x's are the same)

5. its correct though?

6. Originally Posted by Mr_Green
its correct though?
yes, how you expanded before was correct. it's just that the right side should be a number. namely the square of the number i asked you to calculate