Derive the equation (general form) of all points that are equidistant from the point F(-6,3) and the line y = -5.

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- Sep 9th 2007, 08:21 AMMr_GreenDeriving the equation
Derive the equation (general form) of all points that are equidistant from the point F(-6,3) and the line y = -5.

Thanks - Sep 9th 2007, 08:23 AMThePerfectHacker
- Sep 9th 2007, 08:30 AMMr_Green
sqrt[(x+6)^2 + (y-3)^2] = sqrt[(0^2) + (y+5)^2]

square both sides

x^2 + 12x + 36 + y^2 - 6y + 9 = y^2 + 10y +25

x^2 + 12x -16y -11 = 0

Is this correct? - Sep 9th 2007, 09:07 AMJhevon
the distance of (-6,3) to the line y = -5 is the distance between the points (-6,3) and (-6,-5), you don't really need the formula for this, but you can use it if you want to (we are looking for the shortest distance here, which is a vertical line, so the x's are the same)

- Sep 9th 2007, 09:27 AMMr_Green
its correct though?

- Sep 9th 2007, 09:31 AMJhevon