I have a problem, solve for x.
ln(x+2)-2ln(3)=0 ln(x+2)-2ln3=0
So I guess 2ln(3)=2ln
But first I did this because I didn't notice the second equation.
ln(x+2)=2ln(3)
[e^(2ln(3)]=x+2
x=[e^2ln(3)]-2
What do you think?
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I have a problem, solve for x.
ln(x+2)-2ln(3)=0 ln(x+2)-2ln3=0
So I guess 2ln(3)=2ln
But first I did this because I didn't notice the second equation.
ln(x+2)=2ln(3)
[e^(2ln(3)]=x+2
x=[e^2ln(3)]-2
What do you think?
Your solution to solveis fine, but you can simplify it this way:
and therefore
Also notice:
But this statement:
doesn't make sense ... the two given equations are totally equal.