Math Help - how do u solve 4^(3-x)=7?

1. how do u solve 4^(3-x)=7?

how do u solve 4^(3-x)=7?

2. Re: how do u solve 4^(3-x)=7?

Originally Posted by Orlando
how do u solve 4^(3-x)=7?
in this case, by using logarithms

$\log(4^{3-x}) = \log(7)$

now use the properties of logarithms to finish it

3. Re: how do u solve 4^(3-x)=7?

RULE: if a^x = b then x = log(b) / log(a)