See if you can hammer it into this shape: $\displaystyle 9(x+2y+z)^{2}-16(x-2y+z)^{2}=(14y-x-z)(7x-2y+7z)$
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Originally Posted by CaptainBlack No real factors You sure? $\displaystyle 3v^2-11v-10 $ It has real roots
Originally Posted by galactus See if you can hammer it into this shape: $\displaystyle 9(x+2y+z)^{2}-16(x-2y+z)^{2}=(14y-x-z)(7x-2y+7z)$ I ended up getting (7x - 2y + 7z)(7x - 2y + 7z) I went wrong somewhere. :S EDIT: Nevermind, had my signs confused. I did end up getting (14y - x - z)(7x - 2y + 7z).
Last edited by Jeavus; Sep 8th 2007 at 09:08 AM.
Originally Posted by Krizalid You sure? $\displaystyle 3v^2-11v-10 $ It has real roots Oppss.. no rational factors RonL
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