please simplify (1.2x^3+4.5x^2-3.8x)+(-3.4x^3-4.7x^2+23)
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The . indicate decimal points I assume? If so simply group and add like terms $\displaystyle 1.2x^3+-3.4x^3 = -2.2x^3$ do the same for different orders of $\displaystyle x$
What about this one..... -4x(2x^3-6x^2-5x+1)
Originally Posted by Pandatwirler2 What about this one..... -4x(2x^3-6x^2-5x+1) 2x^3-6x^2-5x+1 isn't factorable.
Originally Posted by Pandatwirler2 What about this one..... -4x(2x^3-6x^2-5x+1) You can expand the $\displaystyle -4x$ into the bracket here, $\displaystyle -4x(2x^3-6x^2-5x+1) = -4x\times 2x^3-4x\times-6x^2-4x\times-5x-4x\times 1 = \dots$ Is that what you are after?
yes but how do you multiply -4x with 2x^3?
you multiply the coefficients and add the exponents $\displaystyle (-4x)(2x^3) = -8x^4$
Originally Posted by Pandatwirler2 yes but how do you multiply -4x with 2x^3? Has you teacher not told you how?
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