3/8 multiplied by x minus 1=4
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Is $\displaystyle \displaystyle\frac{3}{8}x-1=4$ or $\displaystyle \displaystyle\frac{3}{8}(x-1)=4$ ?
its the first one you wrote
Multiply by 8: $\displaystyle 3x-8=32$ Can you continue?
yeah thanks!
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