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Math Help - sum of squares

  1. #1
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    Post sum of squares

    suppose 'n' is a positive integer and (2n+1) is the square of an integer. show that (n+1) is the sum of squares of two integers
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  2. #2
    MHF Contributor red_dog's Avatar
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    2n+1=k^2
    The left side is an odd number, so k=2p+1.
    Then 2n+1=4p^2+4p+1\Rightarrow n=2p^2+2p\Rightarrow n+1=2p^2+2p+1=p^2+(p+1)^2
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