I have four problems I need help on:
5a^2/3*4a^3/2
(I believe it's multiplying, the copier messed up)
4a^5/3^3/2
log5(3x+1)=2
(It's log Base 5, as in the 5 there should be below the rest of the equation)
Log5x(x-1)=2
(This is base 10)
I have four problems I need help on:
5a^2/3*4a^3/2
(I believe it's multiplying, the copier messed up)
4a^5/3^3/2
log5(3x+1)=2
(It's log Base 5, as in the 5 there should be below the rest of the equation)
Log5x(x-1)=2
(This is base 10)
Do you have to simplify the exercice(s) with the exponents?
For the logarithmic equations, use: $\displaystyle \log_a(x)=y \Leftrightarrow a^y=x$
For example the second one:
$\displaystyle \log_5(3x+1)=2 \Leftrightarrow 5^2=3x+1 \Leftrightarrow ... $
(and offcourse if you want to do the solution check: $\displaystyle 3x+1>0$)
Then you've to know the basic rules like for example $\displaystyle a^{x}\cdot a^{y}=a^{x+y}$, ... .
Can you continue with the hint I gave about the logarithmic equations?
Try to do some work by yourself, that's the best way to learn something.
Right! $\displaystyle x=-4$ and $\displaystyle x=5$ are indeed the solutions (don't forget to check them!)
But your first exercice is not clear, because you're not using brackets.
I guess you've to simplify:
$\displaystyle \frac{5a^2}{3}\cdot \frac{4a^3}{2}$
(to simplify, look at the 'basic rule' I gave in one of my previous posts)