i got a question:
E = log N^2 / t
(thats log base 2)
How would i make t the subject,
what i did was:
> E*t = log N^2
> t = log N^2 / E
But i dont think its right?
Hello, taurus!
You're expected to know this identity: .$\displaystyle \log_b(Y) \,= \,x\quad\Rightarrow\quad b^x \,=\,Y$$\displaystyle E \:= \;\log_2\left(\frac{N^2}{t}\right)$ . . Solve for $\displaystyle t$.
So we have: .$\displaystyle \log_2\left(\frac{N^2}{t}\right) \:=\:E\quad\Rightarrow\quad 2^E \:=\:\frac{N^2}{t}$
Now solve for $\displaystyle t$.