# logs

• Sep 6th 2007, 07:32 PM
taurus
logs
i got a question:

E = log N^2 / t

(thats log base 2)
How would i make t the subject,

what i did was:
> E*t = log N^2
> t = log N^2 / E

But i dont think its right?
• Sep 6th 2007, 07:45 PM
Jhevon
Quote:

Originally Posted by taurus
i got a question:

E = log N^2 / t

(thats log base 2)
How would i make t the subject,

what i did was:
> E*t = log N^2
> t = log N^2 / E

But i dont think its right?

why do you have "^" indicating the base? "^" indicates a superscript you know.

do you mean $\displaystyle E = \frac {\log_2 N}{t}$ or $\displaystyle E = \log_2 \left( \frac {N}{t} \right)$?

if you meant the first one, you are correct
• Sep 6th 2007, 08:22 PM
taurus
the second one but N squared
• Sep 7th 2007, 02:35 AM
taurus
$\displaystyle E = \log_2 \left( \frac {N^2}{t} \right)$?
• Sep 7th 2007, 03:00 AM
Soroban
Hello, taurus!

Quote:

$\displaystyle E \:= \;\log_2\left(\frac{N^2}{t}\right)$ . . Solve for $\displaystyle t$.
You're expected to know this identity: .$\displaystyle \log_b(Y) \,= \,x\quad\Rightarrow\quad b^x \,=\,Y$

So we have: .$\displaystyle \log_2\left(\frac{N^2}{t}\right) \:=\:E\quad\Rightarrow\quad 2^E \:=\:\frac{N^2}{t}$

Now solve for $\displaystyle t$.