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- Sep 6th 2007, 07:05 PMRevelsynexponent problem
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- Sep 6th 2007, 07:06 PMJhevon
when multiplying numbers of the same base, we add the powers. that is,

$\displaystyle \displaystyle x^a \times x^b = x^{a + b}$

Note, $\displaystyle 2^{-n} \left( 2^n - 2^{1 + n} \right) = 2^{-n} \cdot 2^n - 2^{-n} \cdot 2^{1 + n}$

Now continue using the rule above - Sep 6th 2007, 07:19 PMRevelsyn
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- Sep 7th 2007, 05:38 AMKrizalid
Didn't we see this before?

- Sep 7th 2007, 09:44 AMtopsquark
- Sep 7th 2007, 05:44 PMRevelsyn
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