$\displaystyle \sqrt{2x+2}-\sqrt{x-3}=2$

$\displaystyle \left(\sqrt{2x+2}\right)^{2}=\left(2+\sqrt{x-3}\right)^{2}$

$\displaystyle x+1=4\sqrt{x-3}$

i dont know where to go from here, i tried dividing by 4 and mult. the left by itself, and get lost, the answer is 7