Do you follow up to there? If so, what do you get on the RHS?
Here is the problem I have: -7 x [sqr root of (3x-8)] + 3 = -4x + 7. The answer I am looking for is 8. I first subtracted 3 then divided the right side by -7. Then I squared both sides and attempted to simplify. I didn't come up with the right answer.
Yes, I follow up to there. I personally didn't break up the denominator into a fraction as you did. I get 16/49 times x^2 - 2x + 1 on the RHS. I tried distributing the fraction over and I got the wrong answer again... I don't know what I'm doing wrongly. I've worked this at least 10 times, coming with the quadratic and plugging 8 in, and haven't been successful.
Hello, benny92000!
Whenever possible, I would avoid fractions.
Subtract 3 from both sides: .
Square both sides: .
. . . . . . . . . . . . . . . . . .
Simplify:. a . . . .
Factor:. - . . . . . .
And we have: .
. . and both answers check out!