I hope this image will show through nicely:

Attachment 22010

I've done so far:

1/100 = e^-kt

ln (1/100) = ln e^-kt

-kt = ln(1/100)/ln e

t = ln(1/100)/ln e * -k

Am I right? Maybe ln e needs to be cancelled to something? Please help me out here.

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- Aug 9th 2011, 07:02 AMAluminiumExponential with E^-kt, solving for t
I hope this image will show through nicely:

Attachment 22010

I've done so far:

1/100 = e^-kt

ln (1/100) = ln e^-kt

-kt = ln(1/100)/ln e

t = ln(1/100)/ln e * -k

Am I right? Maybe ln e needs to be cancelled to something? Please help me out here. - Aug 9th 2011, 07:10 AMskeeterRe: Exponential with E^-kt, solving for t
- Aug 9th 2011, 07:15 AMPlatoRe: Exponential with E^-kt, solving for t
- Aug 9th 2011, 07:41 AMAluminiumRe: Exponential with E^-kt, solving for t
I don't see that yet :(

- Aug 9th 2011, 07:48 AMSironRe: Exponential with E^-kt, solving for t
Well:

$\displaystyle 1=100\cdot e^{-kt} \Leftrightarrow \frac{1}{100}=e^{-kt} \Leftrightarrow 100=\frac{1}{e^{-kt}} \Leftrightarrow 100=e^{kt}$

Can you solve it now for $\displaystyle t$?