If B= A^3 / (A -2) what does 'A' equal?

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- August 8th 2011, 02:42 PMwolfA^3 / (A -2) = B Could someone solve this for 'A' ?
If B= A^3 / (A -2) what does 'A' equal?

- August 8th 2011, 02:54 PMSironRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
Do you want an expression like: so in function of B?

- August 8th 2011, 03:11 PMwolfRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
Yes, I would like the equation solved in terms of A.

For example, if 2A^2 = B, then A = square root (B/2) - August 8th 2011, 03:40 PMSironRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
My first impression says it's not possible.

- August 8th 2011, 03:51 PMPlatoRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
There are some conditions under which a cubic can be solved.

Here is a discussion. - August 8th 2011, 03:53 PMQuackyRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
Possible, but not fun, according to my cheating. It depends on why you'd need it.

- August 8th 2011, 03:54 PMSironRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
- August 8th 2011, 05:09 PMwolfRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
Thank you Siron, Plato and especially Quacky for the link to the answer.

At first that seems as if it's an easy equation to solve but*not*after looking at that answer.

Thanks everyone. - August 9th 2011, 04:35 AMBacteriusRe: A^3 / (A -2) = B Could someone solve this for 'A' ?
Yes polynomials do tend to "look" easy to solve because they have nice round integers as coefficients... but in general solving a polynomial algebraically is not easy. For instance solving is easy, make that and we're all stumped. In fact in practice polynomials are solved by approximation in the real world. But that doesn't mean it's wrong to learn how to solve cubics!