The question: The remainder obtained when 3x^4 + 7x^3 + 8x^2 -2x -3 is divided by x + 1 is?

The answer is 3. My book says to plug in -1 for x (which results with 3). Why should I do this?

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- August 8th 2011, 11:57 AMbenny92000Remainder with polynomial division
The question: The remainder obtained when 3x^4 + 7x^3 + 8x^2 -2x -3 is divided by x + 1 is?

The answer is 3. My book says to plug in -1 for x (which results with 3). Why should I do this? - August 8th 2011, 12:17 PMSironRe: Remainder with polynomial division
Because that's the way you find a remainder.

For example if you want to solve the equation , in first instance you're going to search for a number wherefore , that means if you divide by you'll obtain remainder 0, in this case if you enter -1 you see so the remainder is 3. To have a closer look you can make the Horner scheme. - August 8th 2011, 12:48 PMAlso sprach ZarathustraRe: Remainder with polynomial division
- August 8th 2011, 12:57 PMbenny92000Re: Remainder with polynomial division
Hmm, thanks. Makes a little more sense. I guess I still need to work a few hands-on examples to make sense of why we do that. Let me ask a few questions to get a more thorough understanding:

1.) Why do we set the first equation equal to 0?

2.) Why does dividing by the the x-x1 give us remainder 0? - August 8th 2011, 01:00 PMSironRe: Remainder with polynomial division
That was just an example (another case), and because is a zero therefore if you divive by you'll obtain remainder 0 (this is a theoretical look to it).

- August 8th 2011, 01:49 PMbenny92000Re: Remainder with polynomial division
Oh... Ok. That seems to make sense now. Thanks!

- August 8th 2011, 01:52 PMSironRe: Remainder with polynomial division
You're welcome!

Beside the 'polynomial long division' (see Also sprach Zarathrusta's post) you can also use Horner scheme to evaluate the remainder.