Results 1 to 7 of 7

Math Help - Algebraic Simplification

  1. #1
    Newbie
    Joined
    Jul 2011
    Posts
    19

    Algebraic Simplification

    Okay I've got this:

    y-\sqrt{2}=(y+\sqrt{2})Ce^{-\sqrt{2}x^2}

    and need to make it so that

    y=\frac{\sqrt{2}(1+Ce^{-\sqrt{2}x^2})}{1-Ce^{-\sqrt{2}x^2}}

    Where C is just a constant

    Need helps with then steps involved please...
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Aug 2007
    From
    USA
    Posts
    3,111
    Thanks
    2

    Re: Algebraic Simplification

    Well, do it. What's your first step?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jul 2011
    Posts
    19

    Re: Algebraic Simplification

    Sorry I've no idea lol. Maybe add \sqrt{2} to both sides and try to do something from there? I'm sorry im clueless lol. Sorry if this is supposed to be easy :S
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,591
    Thanks
    1445

    Re: Algebraic Simplification

    \displaystyle \begin{align*}y - \sqrt{2} &= \left(y + \sqrt{2}\right)Ce^{-\sqrt{2}x^2} \\ y - \sqrt{2} &= Cye^{-\sqrt{2}x^2} + C\sqrt{2}e^{-\sqrt{2}x^2} \\ y - Cye^{-\sqrt{2}x^2} &= \sqrt{2} + C\sqrt{2}e^{-\sqrt{2}x^2} \\ y\left(1 - Ce^{-\sqrt{2}x^2}\right) &= \sqrt{2}\left(1 + Ce^{-\sqrt{2}x^2}\right) \end{align*}

    Finish it.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Jul 2011
    Posts
    19

    Re: Algebraic Simplification

    Quote Originally Posted by Prove It View Post
    \displaystyle \begin{align*}y - \sqrt{2} &= \left(y + \sqrt{2}\right)Ce^{-\sqrt{2}x^2} \\ y - \sqrt{2} &= Cye^{-\sqrt{2}x^2} + C\sqrt{2}e^{-\sqrt{2}x^2} \\ y - Cye^{-\sqrt{2}x^2} &= \sqrt{2} + C\sqrt{2}e^{-\sqrt{2}x^2} \\ y\left(1 - Ce^{-\sqrt{2}x^2}\right) &= \sqrt{2}\left(1 + Ce^{-\sqrt{2}x^2}\right) \end{align*}

    Finish it.
    Whoa!!! Multiply out, then take the common factors of \sqrt2 and y!! You're a genious!!!!!!!

    Edit: I'm probably actually just stupid lol, but the former is probably also true!
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,591
    Thanks
    1445

    Re: Algebraic Simplification

    Quote Originally Posted by Umair View Post
    Whoa!!! Multiply out, then take the common factors of \sqrt2 and y!! You're a genious!!!!!!!

    Edit: I'm probably actually just stupid lol, but the former is probably also true!
    Don't call yourself stupid, you'll start believing it ><

    I think you also mean "Genius", not "Genious" :P
    Follow Math Help Forum on Facebook and Google+

  7. #7
    MHF Contributor
    Joined
    Aug 2007
    From
    USA
    Posts
    3,111
    Thanks
    2

    Re: Algebraic Simplification

    Quote Originally Posted by Umair View Post
    I've no idea lol.
    Please see how catastrophic this is. GET an idea. No idea never will be funny. Pay attention in class. Read the material. You WILL have SOME idea.

    Never say or think that again.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. having a problem with algebraic simplification
    Posted in the Calculus Forum
    Replies: 4
    Last Post: November 20th 2011, 03:07 AM
  2. Replies: 1
    Last Post: August 25th 2011, 05:09 AM
  3. Algebraic Simplification
    Posted in the Calculus Forum
    Replies: 20
    Last Post: August 5th 2011, 06:06 AM
  4. Algebraic Simplification
    Posted in the Algebra Forum
    Replies: 1
    Last Post: October 8th 2008, 12:02 PM
  5. Algebraic Simplification
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 26th 2008, 05:03 PM

Search Tags


/mathhelpforum @mathhelpforum