Here is the equation: |x|^2 + 2|x| -3=0

The answer is + or - one. I solved it normally disregarding the abs. value and I got 1 and -3.

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- Aug 7th 2011, 02:44 PMbenny92000Finding real solutions with absolute value
Here is the equation: |x|^2 + 2|x| -3=0

The answer is + or - one. I solved it normally disregarding the abs. value and I got 1 and -3. - Aug 7th 2011, 02:52 PMPlatoRe: Finding real solutions with absolute value
- Aug 7th 2011, 03:09 PMbenny92000Re: Finding real solutions with absolute value
Yes. I guess basic reason will take me from there.

- Aug 7th 2011, 06:50 PMProve ItRe: Finding real solutions with absolute value
Let $\displaystyle \displaystyle X = |x|$ so that your equation becomes $\displaystyle \displaystyle X^2 + 2X - 3 = 0$.

Solve for $\displaystyle \displaystyle X$ and then use that solution to solve for $\displaystyle \displaystyle |x|$.