# Ratio and Fraction {conference and participants}

• Aug 7th 2011, 03:14 AM
fleurdel
Ratio and Fraction {conference and participants}
At a conference made up of speakers and participants, there were 20% more men than women. The ratio of mae speakers to female speakers was 8:5. There was an equal number of male and female participants.

(a) Find the ratio of male speakers to male participants at the conference

(b) Halfway, 40 male participants left the conference and another 60 female participants joined the conference. In the end, there were 3/4 as many male participants as female participants remaining behind. How many speakers were at the conference?

much appreciated.
• Aug 7th 2011, 05:32 AM
mr fantastic
Re: Ratio and Fraction {conference and participants}
Quote:

Originally Posted by fleurdel
At a conference made up of speakers and participants, there were 20% more men than women. The ratio of mae speakers to female speakers was 8:5. There was an equal number of male and female participants.

(a) Find the ratio of male speakers to male participants at the conference

(b) Halfway, 40 male participants left the conference and another 60 female participants joined the conference. In the end, there were 3/4 as many male participants as female participants remaining behind. How many speakers were at the conference?

much appreciated.

M = 6W/5 .... (1)

X/Y = 8/5 .... (2)

M - X = W - Y .... (3)

Use equations (1), (2) and (3) to get the value of X/(M - X).

Use the information in (b) to construct another equation. You now have 4 equations and 4 unknowns. You require the value of X + Y.